Program to calculate the square root of the given number without using the built-in function.

Program to calculate the square root of the given number without using the built-in function.

Program Code:

#include<stdio.h>

#include<conio.h>

#include<math.h>

int main() // Uses Brute-Force Method

{

int s;

double x,d,n;

clrscr();

printf("Enter the number\n");

scanf("%lf",&n);

if(n>=0)

{

for(s=1;s*s<=n;s++); //calculating decimal part of the square root

s--;

for(d = 0.001;d < 1.0;d += 0.001) // calculating the fractional part

{

x = (double)s + d;

if((x*x > (double)n))

{

x = x - 0.001;

break;

}

}

printf("The square root of the given number is %.3lf\n", x);

printf("The square root as per built in function sqrt()is %.2lf", sqrt(n));

}

else

{

printf( "No square root to a negative number");

}

getch();

}

Output:

Enter the number

16

The square root of the given number is 4.000

The square root as per built in function sqrt() is 4.00